A sailor pulls a boat horizontally alongside a dock for 10.0m with a rope angled at 40.0 degrees. He does 766 jules of work. What force did he apply to pull the boat?

Question

Charlie Leblanc

Physics

30 August, 03:37

A sailor pulls a boat horizontally alongside a dock for 10.0m with a rope angled at 40.0 degrees. He does 766 jules of work. What force did he apply to pull the boat?

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Answers (2)

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Marshall Graham · Answer 1

Work is equal to force times the distance. However, the distance here is angled horizontally alongside a dock. And so, we have distance times the cos (theta). The equation is W = Fdcos (theta).

W = Fdcos (theta)

766 J = F (10m) cos (10degrees)

F = 77.78 N

Dylan Allen · Answer 2

For work we use the Formula: W = F. d. cosΘ.

W = 766 J

d = 10m

Θ = 40

766 = F. 10. Cos (40)

F = 766/6.669

F=116.35N

This is what I'm getting the amount of Force used can not be so close to the value of work done.