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17 January, 22:25

An artillery shell is fired at an angle of 62.7

above the horizontal ground with an initial

speed of 1520 m/s.

The acceleration of gravity is 9.8 m/s2.

Find the total time of flight of the shell,

neglecting air resistance.

Answer in units of min ... ?

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Answers (1)
  1. 17 January, 22:40
    0
    This is a motion problem. For bodies in a projectile motion, several equations have already been derived and simplified to account for the behavior of these bodies.

    For the time of flight, the equation is

    t = (2*v*sin (A)) / g

    where

    v = initial velocity of the body

    A = angle of the initial velocity

    g = acceleration due to gravity (9.81 m/s^2)

    t = time of flight

    this formula can also be used if the air resistance can be neglected.

    therefore, substituting the values, we get

    t = 275.65 s or 4.59 min
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