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14 April, 17:08

Show the calculation of the energy involved in melting 120 grams of ice at 0oC if the Heat of Fusion for water is 0.334 kJ/g.

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  1. 14 April, 17:31
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    The energy involved in melting 120 g of ice = 40080 J

    Explanation:

    Heat of fusion of water: Heat of fusion is the heat Energy required to convert a substance from solid to its liquid form without a change in energy.

    The S. I unit of heat of fusion is J/kg.

    Q = lm ... equation 1

    Where Q = Energy involved in melting the ice, l = heat of fusion of water, m = mass of water.

    Given: l = 0.334 kJ/g, m = 120 g

    Substituting these values into equation 1

    Q = 0.334*120

    Q = 40.08 kJ

    Q = 40080 J

    Therefore the energy involved in melting 120 g of ice = 40080 J
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