4.7 cm. The tube is sealed at one end and loaded with lead shot to give it a total mass of M = 130 g. The tube floats in water (of density 1 g/cm3) in vertical position, loaded end down. What is the depth of the bottom end of the tube? Answer in units of cm.

Question

Kaleb

Physics

24 June, 13:45

4.7 cm. The tube is sealed at one end and loaded with lead shot to give it a total mass of M = 130 g. The tube floats in water (of density 1 g/cm3) in vertical position, loaded end down. What is the depth of the bottom end of the tube? Answer in units of cm.

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Answers (1)

Know the Answer?

Colton Christensen · Answer 1

Depth is 7.49cm

Explanation:

Given that;

The diameter of tube is (D) = 4.7cm

Area of the tube is = πD^2/4

Area is 3.142*4.7*4.7/4=17.35cm2

Mass (M) = 130g

Density = 1g/cm^3

Recall that Density = mass / volume

Hence volume = 130/1=130cm^3

Also note

Volume=area*depth

130=17.35*depth

Depth=130/17.35=7.49cm