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15 January, 19:33

An empty capacitor is capable of storing 1.0 * 10-4 J of energy when connected to a certain battery. If the distance between the plates is halved and then filled with a dielectric (κ = 4.3), how much energy could this modified capacitor store when connected to the same battery?

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  1. 15 January, 19:44
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    Energy stored in a capacitor

    = 1/2 C₁V²

    capacity of a capacitor

    c = εK A / d

    k is dielectric and d is distance between plates.

    When the distance between the plates is halved and then filled with a dielectric (κ = 4.3)

    capacity becomes 4.3 x 2 times

    New capacity

    C₂ = 8.6 C₁

    Energy of modified capacitor

    1/2 C₂ V² = 1/2 x 8.6 c x V²

    Energy becomes

    8.6 times.

    Energy stored = 8.6 x 10⁻⁴ J
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