Ask Question
29 March, 12:10

Two oppositely charged parallel metal plates,

1.00 centimeter apart, exert a force with a

magnitude of 3.60 * 10^-15 newton on an electron

placed between the plates. Calculate the

magnitude of the electric field strength between

the plates. [Show all work, including the

equation and substitution with units.]

+2
Answers (1)
  1. 29 March, 12:20
    0
    Electric field strength = Force/Charge

    E = (3.6*10^-15) / (1.6*10^-19) = 2.25*10^4 N/c

    1.6*10^-19 being the elementary charge that is a fundamental constant, and is the charge on an electron.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Two oppositely charged parallel metal plates, 1.00 centimeter apart, exert a force with a magnitude of 3.60 * 10^-15 newton on an electron ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers