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1 March, 00:33

A) A 5.00-kg squid initially at rest ejects 0.250 kg of fluid with a velocity of 10.0 m/s. What is the recoil velocity of the squid if the ejection is done in 0.100 s and there is a 5.00-N frictional force opposing the squid's movement?

(b) How much energy is lost to work done against friction?

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  1. 1 March, 00:42
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    (a) The recoil velocity of the squid is 0.5 m/s

    (b) W = 0.25 J

    Explanation:

    (a)

    Momentum of the squid = momentum of the fluid

    MV = mv

    Where M = mass of the squid, V = recoil velocity of the squid, m = mass of the fluid, v = recoil velocity of the fluid.

    Making V the subject of formula,

    V = mv/M

    Where m = 0.25 kg, M = 5.00 kg, v = 10 m/s

    V = (0.25 * 10) / 5

    V = 0.5 m/s

    The recoil velocity of the squid is 0.5 m/s

    (b)

    Work done against friction (W) = Frictional force (F) * Distance (d)

    W = F * d ... Equation 2

    Where F = 5.0N, d = distance.

    d = velocity * time

    Where Velocity = 0.5 m/s, Time = 0.1 s

    ∴ d = 0.5 * 0.1 = 0.05 m

    Substituting these values into equation 2,

    W = 5 * 0.05

    W = 0.25 J

    Therefore 0.25 J of energy is lost to the work done against friction.
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