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20 March, 13:27

The amount of heat per second conducted from the blood capillaries beneath the skin to the surface is 250 j/s. the energy is transferred a distance of 2.1 * 10-3 m through a body whose surface area is 1.9 m2. assuming that the thermal conductivity is that of body fat, determine the temperature difference between the capillaries and the surface of the skin.

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  1. 20 March, 13:48
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    Heat flux (i) = k. a. temp variation/d

    i = 250 J/s or 250w; d = 2.1 x 10^-3m; A = 1.9m^2; K (Body Fat) = 0.2W/m. Kelvin; Temp. Var. (Delta T) = ?

    -> 250 = 0.2 x 1.9 x deltaT/2.1 x 10^-3

    -> 250 x 2.1 x 10^-3 = 0.38 x deltaT

    -> 525 x 10^-3 = 38x10^-2 x deltaT

    -> deltaT = 525 x 10^-3 / 38 x 10^-2

    -> deltaT = 13.81 x 10^ (-3 - (-2))

    -> deltaT = 13.81 x 10^-1

    -> deltaT = 1.381 K
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