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26 August, 09:42

The pressure of a gas remains constant while the temperature, volume, and internal energy of the gas increase by 57.7 Co, 1.24 x 10⁻³ m³, and 843 J, respectively. The mass of the gas is 21.6 g, and its specific heat capacity (at constant pressure) is 1080 J / (kg Co). Determine the pressure.

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  1. 26 August, 10:09
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    P = 405.67 kPa

    Explanation:

    given,

    change in temperature = 57.7 °C

    volume of the gas = 1.24 x 10⁻³ m³

    Internal energy of the = 843 J

    Cp = 1080 J/Kg. C°

    mass = 21.6 g

    heat capacity

    Q = m Cp ΔT

    Q = 0.0216 x 1080 x 57.7

    Q = 1346.025 J

    according to first law of thermodynamics

    U = Q + W

    W = Q - ΔU

    PΔV = Q - ΔU

    PΔV = 1346.025 - 843

    P x 1.24 x 10⁻³ = 503.0256

    P = 405.67 x 10³ Pa

    P = 405.67 kPa

    The pressure of the gas is equal to P = 405.67 kPa
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