A small hot-air balloon is filled with 1.01*106 l of air (d = 1.20 g/l). as the air in the balloon is heated, it expands to 1.10*106 l. what is the density of the heated air in the balloon?

Volume of air in the balloon 1.01 x 10^6 L

Density of air is 1.20 g/l

Mass = Density X Volume

So mass of the air in the Balloon = (1.01 x 10^6) X 1.20 = 1.212 x 10^6 g

As the air is heated, the volume of air in the balloon expands to 1.10x 10^6 L Density = Mass / voume So the Density of heated air = 1.212 x 10^6 / 1.10x 10^6 = 1.101 g/l The answer is 1.101 g/l.