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6 November, 20:38

On a distant planet, a rock falls in 48.4 s from the top of a 1.10e+02 m cliff to the planet surface below. What is the acceleration due to gravity on this planet? m/s2 What is the final velocity of the rock just before it hits the planet's surface? m/s

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  1. 6 November, 20:58
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    this can be solve using the formala of free fall

    t = sqrt (2y / g)

    where t is the time of fall

    y is the height

    g is the acceleration due to gravity

    48.4 s = sqrt (2 (1.10e+02 m) / g)

    G = 0.0930 m/s2

    The velocity at impact

    V = sqrt (2gy)

    = sqrt (2 (0.0930 m/s2) (1.10e+02 m)

    V = 4.523 m/s
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