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13 March, 22:53

A tennis ball is dropped from 1.62 m above the

ground. It rebounds to a height of 0.963 m.

With what velocity does it hit the ground?

The acceleration of gravity is 9.8 m/s. (Let

down be negative.)

Answer in units of m/s.

ta

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Answers (1)
  1. 13 March, 23:04
    0
    -5.63 m/s

    Explanation:

    Given:

    y₀ = 1.62 m

    y = 0 m

    v₀ = 0 m/s

    a = - 9.8 m/s²

    Find: v

    v² = v₀² + 2a (y - y₀)

    v² = (0 m/s) ² + 2 (-9.8 m/s²) (0 m - 1.62 m)

    v = - 5.63 m/s
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