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30 July, 14:50

Acharged particle moving through a magnetic field at right angles to the field with a speed of 36.2 m/s experiences a magnetic force of 7.38x104 N. Determine the magnetic force on an identical particle when it travels through the same magnetic field with a speed of 12.1 m/s at an angle of 17° relative to the magnetic field. Express your answer in microNewtons.

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  1. 30 July, 15:04
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    7212.3 N

    Explanation:

    F = 7.38 x 10^4 N, v = 36.2 m/s

    Let b be the strength of magnetic field and charge on the particle is q.

    F = q v B Sin theta

    Here theta = 90 degree

    7.38 x 10^4 = q x 36.2 x B x Sin 90

    q B = 2038.7 ... (1)

    Now, theta = 17 degree, v = 12.1 m/s

    F = q v B Sin theta

    F = 2038.7 x 12.1 x Sin 17 (q v = 2038.7 from equation (1)

    F = 7212.3 N
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