A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = - 16t² + 60t + 6. What will the height be at t = 3 seconds?

A.) 35 feet

B.) 40 feet

C.) 42 feet

D.) 45 feet

Question

Elijah

Physics

2 March, 11:16

A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = - 16t² + 60t + 6. What will the height be at t = 3 seconds?

A.) 35 feet

B.) 40 feet

C.) 42 feet

D.) 45 feet

+4

Answers (1)

Know the Answer?

Ariel Riley · Answer 1

To answer the question, directly substitute the value given for t to the given function of height.

h = - 16t² + 60t + 6

h = (-16) (3 s) ² + (60) (3) + 6 = 42

Therefore, the height of the ball after 3 seconds is 42 ft.

A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = - 16t² + 60t + 6. What will the height be at t = 3 seconds?A.) 35 feetB.) 40 feetC.) 42 feetD.) 45 feet

A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = - 16t² + 60t + 6. What will the height be at t = 3 seconds?

A.) 35 feet

B.) 40 feet

C.) 42 feet

D.) 45 feet