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6 September, 14:57

What is the specific heat capacity if it takes 1000 J of energy to heat 25 g of this substance by 100°C? Give your answer in J/kg°C.

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Answers (2)
  1. 6 September, 15:05
    0
    400J/kg°C

    Explanation:

    E = m*c * (change in temperature)

    E = 1000J

    m = 25g = 0.025kg

    Change in temperature = 100

    1000 = 0.025*c*100

    1000=2.5c

    c = 400J/kg°C
  2. 6 September, 15:19
    0
    Answer: 4000J/kg°C

    Explanation:

    The quantity of Heat Energy (Q) required to heat substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

    Thus, Q = MCΦ

    Since,

    Q = 1000joules

    M = 25grams (Convert grams to kilograms)

    1000grams = 1kg

    So, 25grams = (25/1000) kg

    = 0.025kg

    C = ? (Let unknown value be Z)

    Φ = 100°C

    Then, apply Q = MCΦ

    1000j = 0.025kg x Z x 100°C

    1000j = 2.5Kg°C x Z

    Divide both sides by 2.5kg°C

    1000j/2.5kg°C = (2.5Kg°C x Z) / 2.5kg°C

    4000J/kg°C = Z

    Recall that Z is the specific heat capacity of the substance.

    Thus, the specific heat capacity of the substance is 4000J/kg°C
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