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7 October, 11:22

A fugitive tries to hop on a freight train traveling at a constant speed of 5.5 m/s. Just as an empty box car passes him, the fugitive starts from rest and accelerates at a = 2.5 m/s2 to his maximum speed of 8 m/s. (a) How long does it take him to catch up to the empty box car? s (b) What is the distance traveled to reach the box car?

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  1. 7 October, 11:25
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    Th equations to be used here are the following:

    a = (v - v₀) / t

    x = v₀t + 0.5at²

    The speed of the fugitive is the sum of his own speed plus the speed of the train. Thus,

    v₀ = 0 + 5.5 m/s = 5.5 m/s

    v = 8 m/s + 5.5 m/s = 13.5 m/s

    a.) We use the first equation to determine time

    2.5 m/s² = (13.5 m/s - 5.5 m/s) t

    Solving for t,

    t = 3.2 seconds

    b.) We use the answer in a) and the 2nd equation:

    x = (5.5 m/s) (3.2 s) + 0.5 (2.5 m/s²) (3.2 s) ²

    x = 30.4 meters
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