A voltage of 169 V is applied across a 199 μF capacitor. Calculate the charge stored on the capacitor.

Q = 3.363 x 10⁻² C

Explanation:

given,

Voltage, V = 169 V

Capacitance of the capacitor, C = 199 μF

Charge in the capacitor = ?

We know,

Q = CV

Q = 169 x 199 x 10⁻⁶

Q = 3.363 x 10⁻² C

Hence, the Charge stored in the capacitor is equal to Q = 3.363 x 10⁻² C