Ask Question
6 December, 03:52

A parachutist with a camera, both descending at a speed of 10.8 m/s, releases that camera at an altitude of 60 m. In this problem, take "up" to be positive. What is the velocity of the camera just before it hits the ground?

+4
Answers (1)
  1. 6 December, 04:02
    0
    The velocity of the camera just before it hit the ground = 35.97 m/s.

    Explanation:

    Velocity: This can be defined as the ratio of the displacement of a body to the time. Velocity is a vector quantity, and as such it can be represented both in magnitude and direction.

    From the equation of motion,

    v² = u² + 2gs ... Equation 1

    Where v = final velocity, u = initial velocity, g = acceleration due to gravity, s = distance.

    Note: Before the velocity of the camera before it hits the ground = The final velocity of the camera.

    Given: u = 10.8 m/s, s = 60 m. g = 9.81 m/s.

    Substituting into equation 1,

    v² = 10.8² + 2 (9.81) (60)

    v² = 116.64+1177.2

    v² = 1293.84

    v = √ (1293.84)

    v = 35.97 m/s.

    Hence the velocity of the camera just before it hit the ground = 35.97 m/s.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A parachutist with a camera, both descending at a speed of 10.8 m/s, releases that camera at an altitude of 60 m. In this problem, take ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers