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4 July, 20:07

A 72 kg sled is pulled forward from rest by a snowmobile and accelerates at 2.0m/s^2 (forward) for 5.0 seconds. The force of friction acting on sled is 120 N (backwards). The total mass of a snowmobile and driver is 450 kg. The drag force acting on snowmobile is 540 N (backwards). Determine the tension in the rope and the force exerted by the snowmobile that pushes the sled forward.

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  1. 4 July, 20:09
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    The total force needed to pull the sled is equal to mass*acceleration plus the force of friction

    F_sled = 72kg * 2.0m/s + 120 N = 260 N

    Since the tension of the rope must be equal to the force that pulls the sled

    tension in the rope = 260N

    The force exerted by the snowmobile is equal to the drag force plus its mass times acceleration

    F-snowmobile only = 450kg * 2.0m/s + 540N = 1440 N

    F-snowmobile and sled = 1440N + 260 N = 1700 N
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