When you sneeze, the air in your lungs accelerates from rest to approximately 160 km/hr in about 0.55 seconds. what is the acceleration of the air in m/s2?

Change in velocity, Δv = 160 km/hr

Change in time, Δt = 0.55 s

Note that

1 km = 1000 m

1 h = 3600 s

Therefore

Δv = (160,000 m/h) * (1/3600 h/s) = 44.4444 m/s

By definition, the acceleration is

a = Δv/Δt = (44.4444 m/s) / (0.55 s) = 80.808 m/s²

Answer: 80.8 m/s² (nearest tenth)