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19 August, 17:55

A normal walking speed is around 2.0 m/s. how much time t does it take the box to reach this speed if it has the acceleration 5.54 m/s2 that you calculated above?

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  1. 19 August, 18:20
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    Given:

    u (initial velocity) = 0

    a=5.54m/s^2

    v (final velocity) = 2 m/s

    v=u + at

    Where v is the final velocity.

    u is the initial velocity

    a is the acceleration.

    t is the time

    2=0+5.54t

    t=2/5.54

    t=0.36 sec
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