A car initially moving at 35 km/h along a straight highway. To pass another car, it speeds up to 135 km/h in 10.5 seconds at a constant acceleration. How large was the acceleration in m/s^2? How large was the acceleration in units of g = 9.80 m/s^2

Question

Zachariah

Physics

31 July, 08:02

A car initially moving at 35 km/h along a straight highway. To pass another car, it speeds up to 135 km/h in 10.5 seconds at a constant acceleration. How large was the acceleration in m/s^2? How large was the acceleration in units of g = 9.80 m/s^2

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Answers (1)

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Ansley · Answer 1

We calculate the difference between the two velocities,

135 km/h - 35 km/h = 100 km/h

Then, convert the difference into units of m/s

100 km/h x (1000 m / 1 km) x (1 hour / 3600 s) = 27.78 m/s

Then divide the difference by time.

acceleration = 27.78 m/s / 10.5 s = 2.65 m/s²

(2) In terms of g,

x = 2.65 / 9.80 = 0.27

Therefore, the answer would be,

a = 0.27g