A person drives to the top of a mountain. On the way up, the personÍs ears fail to ñpop,î or equalize the pressure of the inner ear with the outside atmosphere. The pressure of the atmosphere drops from 1.010 x 105 Pa at the bottom of the mountain to 0.998 x 105 Pa at the top. Each eardrum has a radius of 0.40 cm. What is the pressure difference between the inner and outer ear at the top of the mountain?

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20 July, 06:59

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Apollo · Answer 1

The pressure on the inner ear is 1.010x10^5 -.998x10^5 = 1200Pa outward

So the net force = P*A = 1200Pa*π * (0.40x10^-2m) ^2 = 0.0603N