The moment of inertia of a cylinder is 0.016 kg m^2 with radius 6.0 cm. If the cylinder has a linear speed is 7.7 m/s, what is the magnitude of the angular momentum of the cylinder?

2.05 kgm²/s

Explanation:

I = moment of inertia of cylinder = 0.016 kgm²

r = radius of the cylinder = 6 cm = 0.06 m

v = linear speed of the cylinder = 7.7 m/s

w = angular speed of cylinder

Using the equation

v = r w

7.7 = (0.06) w

w = 128.33 rad/s

Magnitude of angular momentum of the cylinder is given as

L = I w

L = (0.016) (128.33)

L = 2.05 kgm²/s