Ask Question
12 November, 01:02

Sergei tees off on a stationary hockey puck using his most powerful slap shot. If he can exert a force of 250 N on the 500 gram puck for a time of 0.1 seconds, what velocity will he give to it, and how far will the puck move in the time it is on his stick?

+3
Answers (1)
  1. 12 November, 01:05
    0
    Answer: velocity = 50m/s

    Distance moved=5m

    Explanation:

    Using the formula Ft=Mv i. e impulse = momentum

    Where F = force, t = time, M = mass, v = velocity

    In this case we need to find v,

    F, t, M are all given in the question.

    Therefore, substituting the values we have

    250N*0.1s=0.5kg*v. Mass=500g = 0.5kg

    v=25/0.5 = 50m/s

    The distance the puck will move when it is on his stick.

    D = Velocity * time

    D=50m/s * 0.1s

    D=5m

    Goodluck ...
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Sergei tees off on a stationary hockey puck using his most powerful slap shot. If he can exert a force of 250 N on the 500 gram puck for a ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers