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11 August, 01:36

A local ice hockey pond is at 4°C when the air temperature falls, causing the water temperature to drop to 0°C with 10.9 cm of ice forming at the surface at a temperature of 0°C. How much heat was lost if the unfrozen pond is 1 m deep and 50 m on each side?

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  1. 11 August, 02:00
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    Answer: 114.4 GJ

    Explanation:

    Heat loss Q=U*A*ΔT

    Heat loss of size A is determined by the U value of materials and the difference in temperature.

    From 10.9cm from the ice

    50m = 5000cm

    A = 5000*5000

    Q= = (10.9) (5000) (5000) (4.184) (1*4 + 80)

    Q = 95,771,760,000J

    Q≈ 95.8 GJ

    Linear gradient from the bottom of the pond to the ice:

    Q = (89.1) (5000) (5000) (4.184) (1*2)

    Q = 18,639,720,000J

    Q ≈ 18.6 GJ

    Total heat loss:

    Q = 95.8GJ + 18.6GJ

    Q = 114.4 GJ
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