A bullet is fired straight up from a gun with amuzzle velocity of 208 m/s. Neglecting air resistance, what will be itsdisplacement after 8.9 s?

Displacement after 8.9 seconds is 1462.68 m

Explanation:

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 208 m/s

Acceleration, a = - 9.81 m/s²

Time, t = 8.9 s

Substituting

s = ut + 0.5 at²

s = 208 x 8.9 + 0.5 x - 9.81 x 8.9²

s = 1462.68 m

Displacement after 8.9 seconds is 1462.68 m