Ask Question
30 September, 08:42

It is 6.00 km from your home to the physics lab. as part of your physical fitness program, you could run that distance at 10.0 km/hr (which uses up energy at the rate of 700 w), or you could walk it leisurely at 3.00 km/hr (which uses energy at 290 w).

+2
Answers (1)
  1. 30 September, 09:01
    0
    1.) It is 6.00km from your home to the physics lab. As part of your physical fitness program, you could run that distance at 10.0km/hr (which uses up energy at the rate of 700W), or you could walk it leisurely at 3.00km/hr (which uses energy at 290 W). A.) Which choice would burn up more energy? running or walking? b.) How much energy (in joules) would it burn? c.) Why is it that the more intense exercise actually burns up less energy than the less intense one? Follow 2 answers Report Abuse Answers billrussell42 Best Answer: running, at 10 km/hour for 6 km is 6 km / 10 km/hour = 0.6 hour or 36 min energy used is 700 watts or 700 joules/s x 36 min x 60s/min = 1.512e6 joules or 1.5 MJ walking, at 3 km/hour for 6 km 6 km / 3 km/hour = 2 hour or 120 min energy used is 290 watts or 290 joules/s x 120 min x 60s/min = 1.872e6 joules or 1.8 MJ C) should be obvious PS, this has nothing to do with potential energy. billrussell42 · 5 years ago 0 Thumbs up 1 Thumbs down Report Abuse Comment Simon van Dijk I assume the watt consumption is per hour. Then running 6km at 10.0 km/h results in 700*6/10 = 420 w. h and walking in 290*6/3 = 580 w. h So walking would burn up more energy (kwh) b) 1 kilowatt hour = 3 600 000 joules so 420 wh = 0.42 kwh = 1.51.10^6 joule c) when you put more effort in making the distance your energy is used more efficient. Simon van Dijk · 5 years ago 0 Thumbs up 2 Thumbs down Report Abuse Comment
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “It is 6.00 km from your home to the physics lab. as part of your physical fitness program, you could run that distance at 10.0 km/hr (which ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers