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21 June, 03:03

An underwater air bubble has an excess inside pressure of 13 pa. what is the excess pressure inside an air bubble with twice the radius?

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  1. 21 June, 03:05
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    Pressure = 2 * pi * sigma * radius where sigma is the pressure constant of the medium or the material.

    Thus, Pressure/Radius = constant

    Based on this:

    (pressure*radius) in case 1 = (pressure*radius) in case 2

    (13 * R) = (P * 2R)

    P = 13/2 = 6.5 pa
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