What mass of water will change its temperature by 20.0 degrees Celsius when 515 J of heat is added to it? the specific heat of water is 4.18J/g*C.

The problem can be solve using the formula:

q = m Cp T

where q is the heat added to the substance

m is the mass of the substance

Cp is the specific of the substance

T is the change in temperature of the subtance

q = m Cp T

515 = m (4.18) (20)

m = 515 / (4.18) (20)

m = 6.16 g of water