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17 December, 05:44

If a 1000-kg car was moving at 30 m/s, what would be its kinetic energy expressed in the unusual (for kinetic energy) units of calories? (1 cal = 4.186 J)

a. 3.0 * 104

b. 9.0 * 105

c. 3.8 * 106

d. 1.1 * 105

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Answers (1)
  1. 17 December, 05:56
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    (d). 1.1 * 10⁵ cal.

    Explanation:

    Kinetic Energy of a body: This is the energy of a body i motion. It is measured in Joules.

    It can be expressed mathematically as

    Ke = 1/2mv² ... equation 1

    Where ke = kinetic energy, m = mass in kg, v = velocity in m/s.

    Where m = 1000 kg, v = 30m/s.

    Substiting these values into equation 1,

    Ke = 1/2 (1000) (30) ²

    Ke = 500 * 900 = 450000 J

    If 1 cal = 4.186 J

    4.186 J = 1 cal

    450000 J = (450000 * 1) / 4.186 cal

    = 107501.2 cal. = 1.075 * 10⁵ cal

    The Kinetic Energy is ≈ 1.1 * 10⁵ cal.

    The right option is (d) 1.1 * 10⁵ cal.
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