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11 June, 06:39

A ship leaves a harbor and sails at 23.5 ∘ to the north of due west. After traveling 575 km, how far west is the ship from the harbor?

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  1. 11 June, 07:03
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    D = 527.31 Km

    Explanation:

    given,

    angle of ship, θ = 23.5° N of W

    distance travel in the direction = 575 Km

    Distance of ship in west from harbor = ?

    now,

    Distance of the ship in the west direction

    D = d cos θ

    d = 575 Km

    θ = 23.5°

    inserting all the values

    D = 575 x cos 23.5°

    D = 575 x 0.91706

    D = 527.31 Km

    Hence, the distance travel by the ship in west from harbor is equal to D = 527.31 Km
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