A standard baseball has a circumference of approximately 23 cm. if a baseball had the same mass per unit volume (see tables in section 1-5) as a neutron or a proton, about what would its mass be?

Question

Dalton Villarreal

Physics

15 January, 00:48

A standard baseball has a circumference of approximately 23 cm. if a baseball had the same mass per unit volume (see tables in section 1-5) as a neutron or a proton, about what would its mass be?

+3

Answers (1)

Know the Answer?

Wade Mora · Answer 1

In order to determine the mass of a standard baseball if it had the same density (mass per unit volume) as a proton or neutron, we first determine the volume of the baseball. The formula to be used is V_sphere = (4/3) * pi*r^3. In this case, the radius r can be obtained from the circumference C, C = 2*pi*r. After plugging in C = 23 cm to the equation, we get r = 3.6066 cm. The volume of the baseball is then equal to 205.4625 cm^3.

Next, take note of these necessary information:

Mass of a neutron/proton = 10^-27 kg

Diameter of a neutron/proton = 10^-15 m

Radius of a neutron/proton = [ (10^-15) / 2]*100 = 5x10^-14 cm

Thus, the density, M/V of the neutron/proton is equal to 1.9099x10^12 kg/cm^3. Finally, the mass of the baseball if it was a neutron/proton can be determined by multiplying the density of the neutron/proton with the volume of the baseball. The final answer is then a large value of 3.9241x10^14 kg.