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11 June, 22:05

A potter's wheel has the shape of a solid uniform disk of mass 7 kg and radius 0.65 m. It spins about an axis perpendicular to the disk at its center. A small 2.1 kg lump of very dense clay is dropped onto the wheel at a distance 0.41 m from the axis.

What is the moment of inertia of the system about the axis of spin?

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  1. 11 June, 22:32
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    1.832 kgm^2

    Explanation:

    mass of potter's wheel, M = 7 kg

    radius of wheel, R = 0.65 m

    mass of clay, m = 2.1 kg

    distance of clay from centre, r = 0.41 m

    Moment of inertia = Moment of inertia of disc + moment f inertia of the clay

    I = 1/2 MR^2 + mr^2

    I = 0.5 x 7 x 0.65 x 0.65 + 2.1 x 0.41 x 0.41

    I = 1.47875 + 0.353

    I = 1.832 kgm^2

    Thus, the moment of inertia is 1.832 kgm^2.
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