Calculate the energy needed to change 10 grams of water from 70°C to 110°C. 0.35 kcal

5.7 kcal

350 kcal

5700 kcal

0.44kcal

Explanation:

Heat energy needed can be calculated using H = mc∆t where;

m is the mass of the object = 10g = 0.01kg

c is the specific heat capacity of the object = 4600J/kgK

∆t is the change in temperature = 110°C - 70°C = 40°C

H = 0.01*4600*40

H = 1840Joules

Since 1joule = 0.000239kcal

1840joules = 0.000239*1840

= 0.44Kcal