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31 December, 13:44

You walk with a velocity of 2 m/s north. You see a man approaching you, and from your frame of reference he has a speed of 3 m/s to the south. What is the velocity of the man from the frame of reference of a stationary observer? is it 5m to the south?

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  1. 31 December, 14:07
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    Yep the answer is 5ms^-1

    Suppose that you as A and the other man as B,

    Then, V (B, A) = V (B, E) - V (A, E)

    V (B, E) = V (B, A) + V (A, E)

    = 3 + 2

    = 5 ms^-1
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