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18 January, 21:41

A 5.5 kg box is pushed across the lunch table. The acceleration of the box is 4.2 m/s2. What was the net force applied to the box?

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  1. 18 January, 21:43
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    Use this numbers that you are given and plug them into the formule for net force

    Net force = m*a (mass times acceleration)

    Therefore the net force is equal to (5.5 kg) * (4.2 m/s^2) = 23.1 N

    Answer: Net force = 23.1 N
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