Consider two objects (object 1 and object 2) moving in the same direction on a frictionless surface. object 1 moves with speed v1=v and has mass m1=2m. object 2 moves with speed v2=2√v and has mass m2=m. part a which object has the larger magnitude of its momentum?

Question

Cassius Mclaughlin

Physics

1 May, 00:54

Consider two objects (object 1 and object 2) moving in the same direction on a frictionless surface. object 1 moves with speed v1=v and has mass m1=2m. object 2 moves with speed v2=2√v and has mass m2=m. part a which object has the larger magnitude of its momentum?

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Finley Skinner · Answer 1

By definition, we know that momentum is given by p = m * v. Then, for object 1, we have p1 = (2 * m) * (v) = 2mv and for object 2 we have p2 = (m) * (sqrt (2) v) = m*sqrt (2) v. Therefore, the moment magnitude for object 1 is greater than object 2 p1 > p2