What is the magnitude of the speed of a person standing at the equator due to the rotational speed of Mars? (Assume a Mars day is the same length as an Earth day)

Note:

The equatorial diameter of the earth is 12,756 km.

Therefore the equatorial radius is

r = 12756/2 = 6378 km.

The angular velocity of the earth is

ω = (2π radians) / (24 hours) = 0.2618 rad/h

The tangential velocity of a person at the equator is

v = rω

= (6378 km) * (0.2618 rad/h)

= 1670 km/h

Answer: 1670 km/h