A cargo elevator on Earth (where g = 10 m/s2) lifts 3000 kg upwards by 20 m. 720 kJ of electrical energy is used up in the process. What is the efficiency of this process?

Question

Maliyah

Physics

24 July, 01:24

A cargo elevator on Earth (where g = 10 m/s2) lifts 3000 kg upwards by 20 m. 720 kJ of electrical energy is used up in the process. What is the efficiency of this process?

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Answers (1)

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Ashlyn Schaefer · Answer 1

Answer: 83%

Explanation:

Efficiency of the process = work output/work input * 100%

Work input is the energy used up in the process = 720,000Joules

Work output = Force * distance

= (3000*10) * 20

= 600000 Joules

Efficiency = 600000/720000 * 100

= 0.83*100

= 83%