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21 October, 06:09

How much work does a motor do as it lifts a 675-kilogram elevator from a height of 15 meters to a height of 35 meters?

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  1. 21 October, 06:39
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    Work is defined as Force x Distance

    W = Fd

    so (675kg) (9.8m/s^2) = 6615 N

    d = 35-15 = 20m

    so

    W = Fd

    (6615N) (20m)

    132,300 J = W
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