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21 July, 10:20

The minimum stopping distance of a car moving at 20.5 mi/h is 11.6 m. Under the same conditions (so that the maximum braking force is the same), what is the minimum stopping distance for 50.2 mi/h?

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  1. 21 July, 10:23
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    d = 69.57 meter

    Explanation:

    First case

    Speed of car (v) = 20.5 mi/h = 9.164 M/S

    distance (d) = 11.6 meter (m = mass of the car)

    Work done = 0.5 m v² = 0.5 * 9.164² * m J = 41.99 m J

    Force = (workdone / distance) = (41.99 m / 11.6) = 3.619 m N

    Second case

    v = 50.2 mi/h = 22.44135 m/s

    d = ?

    Work done = 0.5 * 22.44² * m J = 251.7768 * m J

    Since the braking force remains the same.

    3.619 m = (251.7768 m / d)

    d = 69.57 meter
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