Calculate the earth's gravity force on a 75 kg astronaut who is repairing the hubble space telescope 600 km above the earth's surface express your answer using two significant figures.

Given: Mass of the astronaut Ma = 75 Kg

Radius of the earth re = 6.38 x 10⁶ m

Altitude of the astronaut h = 600 Km = 600,000 m

Total radius will be r = 6.38 x 10⁶ m + 600,000 r = 6.98 x 10⁶ m

G = 6.67 x 10⁻¹¹ N. m²/Kg²

Mass of Earth Me = 5.98 x 10²⁴ Kg

Formula: F = GmeMa/re²

F = (6.67 X 10⁻¹¹ N. m²/Kg²) (5.98 X 10²⁴ Kg) (75 Kg) / (6.98 x 10⁶ m) ²

F = 2.99 x 10¹⁶ N. m²/4.87 x 10¹³ m²

F = 613.96 N or around 615 N