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Today, 20:48

A blacksmith heats a 1.5 kg iron horseshoe to 500 C, containing 20 kg of water at 18 C then plunges it into a bucket What is the equilbrlum temperature? Express your answer using two significant figures.

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  1. Today, 20:50
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    21.85 C

    Explanation:

    mass of iron = 1.5 kg, initial temperature of iron, T1 = 500 C

    mass of water = 20 kg, initial temperature of water, T2 = 18 C

    let T be the equilibrium temperature.

    Specific heat of iron = 449 J/kg C

    specific heat of water = 4186 J/kg C

    Use the principle of caloriemetry

    heat lost by the hot body = heat gained by the cold body

    mass of iron x specific heat of iron x decrease in temperature = mass of water x specific heat of water x increase in temperature

    1.5 x 449 x (500 - T) = 20 x 4186 x (T - 18)

    336750 - 673.5 T = 83720 T - 1506960

    1843710 = 84393.5 T

    T = 21.85 C
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