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24 March, 21:04

When the Glen Canyon hydroelectric power plant in Arizona is running at capacity, 690 m3 of water flows through the dam each second. The water is released 220 m below the top of the reservoir.

Part A

If the generators that the dam employs are 90% efficient, what is the maximum possible electric power output?

Express your answer with the appropriate units.

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Answers (1)
  1. 24 March, 21:24
    0
    1340.2MW

    Explanation:

    Hi!

    To solve this problem follow the steps below!

    1 finds the maximum maximum power, using the hydraulic power equation which is the product of the flow rate by height by the specific weight of fluid

    W=αhQ

    α=specific weight for water = 9.81KN/m^3

    h=height=220m

    Q=flow=690m^3/s

    W = (690) (220) (9.81) = 1489158Kw=1489.16MW

    2. Taking into account that the generator has a 90% efficiency, Find the real power by multiplying the ideal power by the efficiency of the electric generator

    Wr = (0.9) (1489.16MW) = 1340.2MW

    the maximum possible electric power output is 1340.2MW
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