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5 October, 19:12

Determine the heat energy required to vaporize 13.9 grams of liquid water at 100° C. O 2,006 cal O 47.8 cal O 7,506 cal O 24.9 cal

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  1. 5 October, 19:37
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    7506 cal

    Explanation:

    Given: Mass of water = m = 13.9 grams.

    Heat energy required to determine the conversion of 13.9 grams of water to steam or vapor is m L,

    where L = Latent heat of vaporization of water=540 cal/g.

    Q = mL = (13.9) (540) = 7,506 cal.
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