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7 January, 16:55

Find the moment of inertia Ihoop of a hoop of radius r and mass m with respect to an axis perpendicular to the hoop and passing through its center.

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  1. 7 January, 16:56
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    Answer: MR²

    is the the moment of inertia of a hoop of radius R and mass M with respect to an axis perpendicular to the hoop and passing through its center

    Explanation:

    Since in the hoop, all mass elements are situated at the same distance from the centre, the following expression for the moment of inertia can be written as follows.

    I = ∫ r² dm

    = R²∫ dm

    MR²

    where M is total mass and R is radius of the hoop.
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