You need to determine the density of a ceramic statue. If you suspend it from a spring scale, the scale reads 28.4 NN. If you then lower the statue into a tub of water, so that it is completely submerged, the scale reads 17.0 NN.

Question

Keyon Abbott

Physics

6 December, 01:33

You need to determine the density of a ceramic statue. If you suspend it from a spring scale, the scale reads 28.4 NN. If you then lower the statue into a tub of water, so that it is completely submerged, the scale reads 17.0 NN.

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Answers (1)

Know the Answer?

Ramon Rush · Answer 1

2491.23 kg/m³

Explanation:

From Archimedes principle,

R. d = weight of object in air / upthrust in water = density of the object/density of water

⇒ W/U = D/D' ... Equation 1

Where W = weight of the ceramic statue, U = upthrust of the ceramic statue in water, D = density of the ceramic statue, D' = density of water.

Making D the subject of the equation,

D = D' (W/U) ... Equation 2

Given: W = 28.4 N, U = lost in weight = weight in air - weight in water

U = 28.4 - 17.0 = 11.4 N,

Constant: D' = 1000 kg/m³.

Substitute into equation 2,

D = 100 (28.4/11.4)

D = 2491.23 kg/m³

Hence the density of the ceramic statue = 2491.23 kg/m³