A ray of red light in air is incident at an angle of 30. on a

boundary with olive oil. What is the angle of refraction, to the

nearest degree, for this light ray in the olive oil?

a 60

§ 20

C 30°

x

do

e 47

20 degrees.

Explanation:

From Snell's law of refraction:

sinθ1•n1 = sinθ2•n2

where θ1 is the incidence angle, θ2 is the refraction angle, n1 is the refraction index of light in medium1, and n2 is the refraction index for virgin olive oil. The incidence angle of the red light is θ1 = 30 degrees.

The red light is in air as medium1, so n1 (air) = 1.00029

So, to find θ2, the refracted angle:

sinθ1•1.00029 = sinθ2•1.464

sin (30) •1.00029 / 1.464 = sinθ2

0.5•1.00029 / 1.464 = sinθ2

sinθ2 = 0.3416291

θ2 = arcsin (0.3416291)

θ2 = 19.976 degrees

To the nearest degree,

θ2 = 20 degrees.