A projectile is fired directly upward from the ground with an initial velocity of 112 f/sec its distance s above the ground after t seconds is given by s (t) = 112t-16t^2 At what time, in seconds, does the projectile achieve its maximum height?

Question

Gretchen Reid

Physics

1 May, 11:22

A projectile is fired directly upward from the ground with an initial velocity of 112 f/sec its distance s above the ground after t seconds is given by s (t) = 112t-16t^2 At what time, in seconds, does the projectile achieve its maximum height?

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Answers (1)

Know the Answer?

Krista Hobbs · Answer 1

3.48 seconds

Explanation:

At maximum height Vf=0 m/s

Vf = Vi - g*t

⇒g*t = Vi

⇒t = Vi/g

⇒t = 112/32.17 sec

⇒ t = 3.48 s

so the projectile will achieve its maximum height in 3.48 seconds.